200
200
16
A total of 44 times.
Assume that the pages are numbered 1-145 in order and we don't have any other page numbering system.In every ten pages the digit 5 will appear in the units column once,e.g. 5, 15, 25, 35, 45 etc.That makes 15 fives.In the 50's the digit 5 will also appear in the tens columne.g. 50,51,52,53,54,55,56,57,58,59That makes another 10 fives.Don't worry about page 55, remember we counted the unit's digit 5 first then the ten's digit 5.The book is too short to have digit 5 in the hundreds column.So the digit 5 appears 25 times in the numbering of a 145-page book. == Answer== From 1 to 145, we have 9 one-digit numbers and 100 two-digit numbers and 46 three-digit numbersIn one-digit numbers we have only one chance to have 5.In two-digit numbers we can have 5 in the units place, in the tens place or the both.If we have 5 in the units place, then we can fill up the tens place by the numbers from 1 to 9. So, we get 9 chances.If we have 5 in the hundreds place, then we can fill up the units place by the numbers from 0 to 9. So, we get 10 chances.In three digit numbers, we can’t have 5 in hundreds place and tens place because we have 145 pages in all. So, we can have 5 in units-place only.The hundreds place cannot be filled with any other number except 1.So, we can fill the tens place by the numbers from 0 to 4 only. So, we get 5 chances.In total, 25 times we come across 5. Source: www.icoachmath.com
The pages of a book are numbered from 1 to 128. How many page numbers contain the digit 6?
First 9 pages = 9 digit. That leaves 142 digits. @ 2 digit per page, that is 142/2 = 71 pages with 2-digit numbers. So, 9 pages with 1-digit numbers + 71 pages with 2-digit numbers = 80 pages.
134 times
134 times
About 669 times.
Answer1 x 9 (number of 1 digit numbers) plus 2 x 89 (number of 2 digit numbers) plus 3(number of 3 digit numbers) x 347 = 1228 The correct answer is 1323. Here is how you do it.1 digit numbers = 92 digit numbers = 90 (99-9) number of 2 digit numbers - number of 1 digit numbers3 digit numbers = 378 (477-99) number of 3 digit numbers - number of 1 & 2 digit numbersSo, the solution is:1x9 = 92x90 = 1803x378 = 11349+180+378 = 1323
The word preacher does not appear in the King James Version of the bibles book of Matthew. The word "preach" however does appear four seperate times through out the book of Matthew.
none