Zero. Only the digits 5 and 0 appear in 500.
95
1 digit number: only 1 number 2 digits number: 18 numbers 3 digits number: 76 So there are 95 numbers containing 9.
To find how many times the digit '9' appears between 1 and 500, we can count occurrences in each digit place (hundreds, tens, and units). In the range of 1 to 500, '9' appears in the units place 50 times (9, 19, 29, ..., 499) and in the tens place 40 times (90-99, 190-199, 290-299, 390-399). It does not appear in the hundreds place in this range. Therefore, the total count is 50 + 40 = 90.
The number 500 contains the digit 5 one time, specifically in the hundreds place. Therefore, there is one occurrence of the digit 5 in the number 500.
500 or so.
200
200
95
200
1 digit number: only 1 number 2 digits number: 18 numbers 3 digits number: 76 So there are 95 numbers containing 9.
900
To determine how many times the digit 3 appears from 1 to 500, we need to consider each place value separately. In the units place, the digit 3 appears 50 times (3, 13, 23, ..., 493). In the tens place, the digit 3 appears 5 times in each set of 10 numbers (30, 31, 32, ..., 39), totaling 50 times. In the hundreds place, the digit 3 appears 100 times (300, 301, 302, ..., 399). Therefore, the digit 3 appears 200 times from 1 to 500.
200
The 3 digit numbers under 500 are 100 through 499.
The number 500 contains the digit 5 one time, specifically in the hundreds place. Therefore, there is one occurrence of the digit 5 in the number 500.
500 or so.
500