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The first digit can be any one of four (2, 4, 6, or 8). For each of those . . .
The second digit can be any one of five (0, 2, 4, 6, or 8). For each of those . . .
The third digit can be any one of five (0, 2, 4, 6, or 8). For each of those . . .
The fourth digit can be any one of five (0, 2, 4, 6, or 8).
Total number of possibilities = (4 x 5 x 5 x 5) = 500 .
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How many even 3-digit numbers can be formed from the digits 1 2 3 and 5 if each digit can be used only once?
The final digit must be a 2 to form an even number. The first digit may be any of three remaining digits (1, 3, 5) while the second digit may be any of the two remaining digits. All together, that makes 3*2 = 6 distinct even numbers.
How many 3 digits numbers can be formed from numbers 3 7?
there cant be any numbers fromed becuase you only have 2 numbers if u wanted to be more comlicated u cud go into decimals
How many combinations of numbers can you get with 1189 with one repeating?
You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.
How many 3-digit numbers can made using the digits 2 3 4?
If you can repeat a digit, there are 27. If you can't repeat a digit, there are only 6.
How many three digits numbers contain only 5 and 6?
The only numbers that can be made with ONLY 5 and 6 are 56 and 65. That is because 5 and 6 are only 2 numbers. If you wanted a three digit number, you would have to use double of one number. You could say these numbers: 556 566 565 656 665 Other than that, I do not know.
