There are: 9C6 = 84 combinations
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There are 167960 9 digits combinations between numbers 1 and 20.
(9 x 8 x 7 x 6 x 5 x 4)/(6 x 5 x 4 x 3 x 2) = 84 combinations.
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).
There are 5,040 combinations.