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The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n

Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1)

= 10*9*8*7/(4*3*2*1) = 210

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David Burnham

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Q: How many combinations of 6 numbers are there in 10 numbers?
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Continue Learning about Algebra

How many combinations of 6 numbers are there in 9 numbers?

There are: 9C6 = 84 combinations


How many combinations of 6 numbers are there in 52 numbers What are these combinations?

This questions can be rewritten as 52 choose 6 or 52C6. This is the same as (52!)/(6!(52-6)!) (52!)(6!46!) (52*51*50*49*48*47)/(6*5*4*3*2*1) 14658134400/720 20358520 There are 20,358,520 combinations of 6 numbers in 52 numbers. This treats 1,2,3,4,5,6 and 6,5,4,3,2,1 as the same combination since they are the same set of numbers.


How many combinations of 6 numbers are there in 33?

There are 33C6 = 33*32*31*30*29*28/(6*5*4*3*2*1) = 1,107,568 combinations.


How many 4 digit combinations can you get from numbers 1226?

To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.


How many 10 number combinations can be made out of 10 numbers?

If you are assuming you can repeat any of the numbers then: nx where n=number of options and x= number of spaces using the formula assuming all numbers 0-9 then: 1010 10,000,000,000 is your answer. If numbers can not repeat and have to be used we use the formula: n! Where n is the number of options.Since you want 10 numbers we will do 10! 10! 10*9*8*7*6*5*4*3*2*1 362880 is your answer.