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How many different combinations can you make with 6 digits using the numbers 1 7 9 1 7 and 9?
This is really a question about permuations with repeated elements.
The formula for that is n!/a! b!... where a, b,.. are repeated
So we have 6 elelments with each repeated 2 times. so the number is.
6!/2!2!2!
This is 6x5x4x3x2x1/ 23
so we can cancel out the 4 and the 2.
6x5x3=90
So 90 different numbers.
What else can I help you with?
How many license plate combinations from 3 digits followed by 3 letters?
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
How many possible 5 digit combinations are there using 5 digits?
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
What are all the combinations for the numbers 1204 not using the numbers more than one time?
To find all the combinations of the numbers 1204 without repeating any number, we can use the formula for permutations without repetition. There are 4 digits in the number 1204, so there are 4 factorial (4!) or 24 possible combinations. These combinations would include 1204, 1240, 1024, 1042, 1402, 1420, 2104, 2140, 2014, 2041, 2401, 2410, 4012, 4021, 4102, 4120, 4201, 4210, 1024, 1042, 1204, 1240, 1402, 1420.
How many 3 digit number are formed using the digits 3 5 7?
With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
List of all 4 digit combintions without repeating using only numbers 0-9?
Oh, dude, you wanna list out all the 4-digit combinations without repeating digits from 0 to 9? That's like 10 choose 4, which is 10! / (4!(10-4)!), which equals 210. So, there are 210 unique 4-digit combinations you can make using numbers 0 to 9 without repeating any digits. Cool, right?
How many license plate combinations from 3 digits followed by 3 letters?
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
Will you show me the 10000 different combinations using the numbers 0 through 9 using only 4 digits?
0000 0001 0002 ... 9998 9999
How many combinations of three digits can be made using thirty-two numbers?
32C3 = 4960
If using the numbers 1 through 9 how many different 3 digit combinations can be made?
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
What 4 number combinations can you get by using numbers 0-9?
There are 10C4 = 10*9*8*7/(4*3*2*1) combinations of 4 digits that are all different. That is, 210 of them, and I have no inclination to list them.
How many 3 digit combinations there 0-9?
The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.
How many possable combinations are there using numbers 0-9?
9
How do you make the numbers 1-100 using the digits two zero one and two?
To create the numbers 1-100 using the digits 2, 0, 1, and 2, you can use various combinations and operations. For example, you can form numbers like 1 (by using 2-2+1), 2 (using one of the 2s), 10 (by combining 2 and 0), and higher numbers such as 20 or 21. By creatively using addition, subtraction, and combinations of the digits, you can generate many numbers up to 100. However, some numbers may not be possible with the given digits and operations.
How many 4 digit combinations can be made using numbers 1 2 3 4 6?
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
How many different ten digit number can be formed using the digits zero until nine excluding numbers starting with zero?
If you exclude numbers starting with zero then the first digit must be between 1 and 9 (i.e. 9 combinations). The remaining 9 digits can be any value between 0 and 9 (i.e. 10 combinations).So you can have 9x109 = 9,000,000,000 combinations.
How many different numbers can you make using 5 different digits?
89,999 different numbers i guess
How many possible 5 digit combinations are there using 5 digits?
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
