If you must use all 5 with no repetition, you can make only one pizza. 5C5, the last entry on the 5 row of Pascal's triangle. If you can choose as many toppings as you want, all the way down to none (cheese pizza), then you have 5C0 + 5C1 + 5C2 + 5C3 + 5C4 + 5C5 = 32. Another way to think about it is no toppings would allow one pizza (cheese), one topping would allow two pizzas (cheese, pepperoni), two toppings would allow four pizzas, three toppings would allow eight pizzas, four toppings would allow sixteen, creating an exponential pattern. p = 2 ^ t. So, 10 toppings would permit 1024 different combinations
10
120 5 x 4 x 3 x 2 x1 = Toppings 20 x 6 x 1 = Toppings 120 x 1 = Toppings 120 = Topping Combinations
8 over 3, which is the same as (8 x 7 x 6) / (1 x 2 x 3).
120
4 pizzas
25
There are 7C5 = 7*6/(2*1) = 21 pizzas.
6666
If you must use all 5 with no repetition, you can make only one pizza. 5C5, the last entry on the 5 row of Pascal's triangle. If you can choose as many toppings as you want, all the way down to none (cheese pizza), then you have 5C0 + 5C1 + 5C2 + 5C3 + 5C4 + 5C5 = 32. Another way to think about it is no toppings would allow one pizza (cheese), one topping would allow two pizzas (cheese, pepperoni), two toppings would allow four pizzas, three toppings would allow eight pizzas, four toppings would allow sixteen, creating an exponential pattern. p = 2 ^ t. So, 10 toppings would permit 1024 different combinations
if you have 3 different toppings then 12*11*10 = 1320
as many as you can dream of. each major chain has average of 10 different pizzas. custom ordered pizzas with your choice of toppings. store bought frozen pizzas in endless variety. gourmet pizza shops with their own menus.etc.there are lots of diffrent kinds of pizza
220
8C3 = 8*7*6/(3*2*1) = 56
three
You can top a pizza with many things.... I prefer hot sausage and mushrooms. There are many different toppings that are wonderful. Plain Cheese Pizzas are good too....
You can make 28 = 256 pizzas. Topping 1: You either have it or you don't: two choices. With each choice, for topping 2: You either have it or you don't: two choices. That makes 2*2 or 22 choices. With each choice for the first two, for topping 3: You either have it or you don't: two choices. That makes 2*2*3 or 23 choices. and so on, making 28 choices in all. Note that one choice will comprise no toppings.