2*2*2*2 = 16, counting one with no toppings.
32 combinations. 4 of these will have no toppings, or all three toppings, 12 will have one topping and another 12 will have 2 toppings.
18
16 because 4 times 4 is 16 and you use each one first then the next one and the next one
200 different combinations. :)
2*2*2*2 = 16, counting one with no toppings.
32 combinations. 4 of these will have no toppings, or all three toppings, 12 will have one topping and another 12 will have 2 toppings.
10
16 i think
36
well, you can to topping 1&2, topping 2&3, topping 1&3, topping 1, 2 and 3, and you can also do all three toppings. so that's seven different types for one size pizza, and you can have all combinations in four sizes. that makes a total of 28 different pizza combinations.
it is i love hunter elam
47
If you must use all 5 with no repetition, you can make only one pizza. 5C5, the last entry on the 5 row of Pascal's triangle. If you can choose as many toppings as you want, all the way down to none (cheese pizza), then you have 5C0 + 5C1 + 5C2 + 5C3 + 5C4 + 5C5 = 32. Another way to think about it is no toppings would allow one pizza (cheese), one topping would allow two pizzas (cheese, pepperoni), two toppings would allow four pizzas, three toppings would allow eight pizzas, four toppings would allow sixteen, creating an exponential pattern. p = 2 ^ t. So, 10 toppings would permit 1024 different combinations
13
Mixture!:)
120 5 x 4 x 3 x 2 x1 = Toppings 20 x 6 x 1 = Toppings 120 x 1 = Toppings 120 = Topping Combinations