8C3 = 8*7*6/(3*2*1) = 56
Chat with our AI personalities
There are 7C5 = 7*6/(2*1) = 21 pizzas.
You can make 28 = 256 pizzas. Topping 1: You either have it or you don't: two choices. With each choice, for topping 2: You either have it or you don't: two choices. That makes 2*2 or 22 choices. With each choice for the first two, for topping 3: You either have it or you don't: two choices. That makes 2*2*3 or 23 choices. and so on, making 28 choices in all. Note that one choice will comprise no toppings.
32 combinations. 4 of these will have no toppings, or all three toppings, 12 will have one topping and another 12 will have 2 toppings.
Call the toppings topping A, B, C, and D. Each pizza needs 2 toppings, so first think about topping A. There can be AB, AC, and AD. A is finished. Now think about B. AB=BA so you can't use BA. The remaining are BC and BD. Then think about C. You can't do CA or CB because those are already used with AC and BC. The only one left is CD. With D, everything is already used, so let's stack up all the answers. AB AC AD BC BD CD Count em all up and you get 6 different combinations. Chart it up however you wish.
2*2*2*2 = 16, counting one with no toppings.