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Depends on the t's and e's are different or not.
There are 10 letters and 10 'spaces' for them to be in.
The first space has 10 different candidates.
The second has 9. The 3rd has 8 and so on.
So there are 10! = 3,628,800 different ways to arrange the letters.
That is if the t's and e's are different.
.
If literaturE is the same as litErature, then we have all possibilities twice concerning the e's.
3,628,800 / 2 = 1,814,400
.
The same goes for the t's.
1,814,400 / 2 = 907,200
.
Ergo: 907,200 or 3,628,800 ways.
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