There are four elements: ABC, 1, 3 and 6.
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how do i list 0,1,123,4,34 i proper set notations? and then place the elements in numerical order.
16 Recall that every set is a subset of itself, and the empty set is a subset of every set, so let {1, 2, 3, 4} be the original set. Its subsets are: {} {1} {2} {3} {4} {1, 2} {1, 3} {1, 4} {2, 3} {2, 4} {3, 4} {1, 2, 3} {1, 2, 4} {1, 3, 4} {2, 3, 4} {1, 2, 3, 4} * * * * * A simpler rationale: For any subset, each of the elements can either be in it or not. So, two choices per element. Therefore with 4 elements you have 2*2*2*2 or 24 choices and so 24 subsets.
Well, honey, I hope you're ready for this math lesson. A set with 6 elements can have 2^6, which is 64 subsets. That's right, 64 ways to slice and dice those elements. So, grab a calculator and start counting, darling!
The total no. of reflexive relations on a set A having n elements is 2^n(n-1).Thus, the required no. is 2^20 = 1 048 576
If set b is finite then the cardinality is the number of elements in it. If it is not finite then it depends on whether its elements can be put into 1-to-1 correspondence with the natural numbers (cardinality = Aleph Null) or with irrationals (Aleph-One).