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How many odd integers between 1000 and 9999 have distinct digits?

There are 120 of them.


How many integers from 1 to 1000 have none of their digits repeated?

To find how many integers from 1 to 1000 have none of their digits repeated, we can analyze the problem by considering the number of digits in the integers. For 1-digit numbers (1-9), there are 9 options. For 2-digit numbers (10-99), the first digit can be chosen in 9 ways (1-9), and the second digit in 9 ways (0-9 excluding the first digit), giving 9 × 9 = 81 combinations. For 3-digit numbers (100-999), the first digit can be chosen in 9 ways, the second in 9 ways, and the third in 8 ways, resulting in 9 × 9 × 8 = 648 combinations. Adding these, we find the total: 9 + 81 + 648 = 738 integers with non-repeating digits from 1 to 1000.


How many positive integers less than 1000 have no odd decimal digits?

52


How many integers are there between 100 and 1000 all of whose digits are odd?

There are 125 of them.


How many odd integers between 1000 and 8000 have only non zero digits?

How many


How many positive integers less than 1000 have distinct digits?

10*9*8=720


How many integers between 1000-9999 have distinct digits?

9*9*8*7 = 4536


What is the probability that an odd number between 1000 and 9000 contains no repeated digits?

2016/4000 = 0.504


How many strings of 3 decimal digits do not contain the same 3 digits?

How many strings of three digits are there? 000 to 999, or a total of 1000. How many strings of three digits contain the same three digits? That's 000, 111, 222 ... 999! ten in total. The difference is your answer: 1000-10 = 990.


What is the sum of all the digits between 1000 and 2000?

The sum of all the integers between 1,000 and 2,000 is 1,498,500.


How many positive integers less than 1000 are 6 times the sum of their digits?

There is only 1, the number 54.


How many positive integers less than 1000 are there such that the digits are not strictly increasing order from left to right?

There are 870 such numbers.