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Oh, what a lovely question! To find the number of integers between 1000 and 9999 with all even digits, we can think of each digit place (ones, tens, hundreds, thousands) independently. In each place, we have 5 even digits to choose from (0, 2, 4, 6, 8). So, we have 5 choices for each of the 4 places, giving us a total of 5 x 5 x 5 x 5 = 625 integers with all even digits. Happy counting!
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Earn +20 ptsQ: How many integers between 1000 and 9999 are even digits?
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How many integers with distinct digits are there between 1000 and 9999 such that the absolute value of the difference between the first and the last digit is 1?
952 of them.
How many integers with distinct digits are there between 1000 and 9999 such that the absolute value of the difference between the first and the last digit is 3?
An infinite amount
How many integers between 1000 and 9999 are palindromes?
90 palindromes.
How many numbers in all are there with four digits?
Highest is 9999, lowest is 1000. These and everything between them have four digits. Try subtracting 999 from 9999. If you can´t, there´s always wikianswers.
How many 4-digit positive integers are there?
from 1000 to 9999, ie 9999 - 999 = 9000
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