A rhombus.
abc and cda
33 triangles
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
you can't, because the Pythagorean theorem is for right triangles and the triangles formed by the diagonal of a parallelogram are not right triangles.
4
yes
1. Opposite sides are equal 2. it is a parallelogram 3. all 4 angles (at vertices) are 900 4. diagonals are equal in length 5. diagonals bisect each other 6. triangles formed by a diagonal and 2 sides (opposite side for each triangle) are congruent 7. among the four triangles that are formed by the 2 diagonals, the vertically opposite triangles are congruent 8. if length=breadth, then the rectangle is a square 9. perimeter of the rectangle = 2 * ( length + breadth) 10. area of rectangle = length * breadth
If the triangles are congruent and you match the hypotenera the right way, you can get a rectangle. If the triangles are not congruent, you can't even necessarily get a quadrilateral.
Let's draw the isosceles trapezoid ABCD, where AD ≅ BC, and mADC ≅ mBCD. If we draw the diagonals AC and BD of the trapezoid two congruent triangles are formed, ∆ ADC ≅ ∆ BDC (SAS Postulate: If two sides and the angle between them in one triangle are congruent to the corresponding parts in another triangle, then the triangles are congruent). Since these triangles are congruent, AC ≅ BD.
how many triangles are formed when any parallelogram and it diagonals are drawn
Probably 6 if not 4 if not 8 if not 10.WHO CARES
1. Opposite angles congruent 2. All sides are congruent 3. The diagonals are perpendicular bisectors of each other 4. Diagonals bisect the angles NOTE: Four congruent right triangles are formed with the right angles It has all of the properties of a parallelogram and a kite
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
5 triangles are formed.
Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.
10