Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
82 dimes
If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D
This question cannot be answered.Assume there is1 nickel. There must be 3 more than that in quarters - that makes4 quarters and there are13 dimes---- that adds up to18
15 quarters, 3 dimes
195 dimes
He has 18 quarters (for $4.50)...........and 10 dimes ($1.00)
4 quarters and 4 dimes is $1.40
Mula has 16 dimes and 11 quarters.
1 quarter and 21 dimes or 3 quarters and 16 dimes or 5 quarters and 11 dimes or 7 quarters and 6 dimes or 9 quarters and 1 dime
Chen has 8 nickels, 2 dimes, and 6 quarters.
4 quarters=10 dimes x quarters=85 dimes quarter=10/4 dimes x (10/4 dimes) = 85 dimes x= 85 dimes/(10/4 dimes) x=34 Answer: 34 quarters
to many to count... 100 dimes 1 quarter. 41 quarters. 50 dimes 21 quarters
What kind of question is this exactly?
15 dimes equals 6 quarters.
If 5 dimes to every 8 quarters that is 5 out of every 13 coins dimes and 8 of 13 coins quarters 5/13 x 520 = 200 dimes