There would be an infinite number of rectangles possible
You can't tell the area from knowing the perimeter. There are an infinite number of different rectangles, all with the same perimeter, that all have different areas. Here are a few rectangles that all have perimeters of 42. The last number after each one is its area: 1 cm by 20 cm . . . . . 20 square centimeters 2 x 19 . . . . . 38 3 x 18 . . . . . 54 4 x 17 . . . . . 68 5 x 16 . . . . . 80 10 x 11 . . . 110
38 inch
The perimeter of the larger polygon will have the same ratio to the perimeter of the smaller as the ratio of the corresponding sides. Therefore, the larger polygon will have a perimeter of 30(15/12) = 37.5, or 38 to the justified number of significant digits stated.
Assuming it is rectangle, then the perimeter equal twice the summation of length and width. Answer = 2 x (14 + 24) = 2 x 38 = 76 inches
By definition the perimeter = n (side length)For a hexagonal, n = 6 Accordingly, side length = perimeter/66 equal sides total 228 inches - each side is 228/6 = 38 inches
62 x 38 = 2356 rectangles
I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.
Perimeter = 38+17+38+17 = 110 units of measurement
An 11 x 8 rectangle will have a perimeter of 38. Add all 4 sides together to get the perimeter,
(38/4) sqrd
A shape on a piece of paper has a perimeter. A pair of numbers doesn't have a perimeter.
The perimeter is 38.
Perimeter: 9+10+9+10 = 38 feet
You can't tell the area from knowing the perimeter. There are an infinite number of different rectangles, all with the same perimeter, that all have different areas. Here are a few rectangles that all have perimeters of 42. The last number after each one is its area: 1 cm by 20 cm . . . . . 20 square centimeters 2 x 19 . . . . . 38 3 x 18 . . . . . 54 4 x 17 . . . . . 68 5 x 16 . . . . . 80 10 x 11 . . . 110
The area of square is : 12544.0
38 diagonals
38 inch