None because without an equality sign it is not an equation and so therefore no solutions are possible.
how many solutions does the equation have? 4x+1=5+2(2-4) a. one solution b. infinite solutions c. no solution
4x-7=5x-2 x=-5
7
4x - 3 - 5x + 7 = 6 4x - 5x = 3 - 7 + 6 -1x = 2 x = -2
(2x - 7)(x + 1)
how many solutions does the equation have? 4x+1=5+2(2-4) a. one solution b. infinite solutions c. no solution
4x-9(x plus 1)7-5x?
If you mean: 2x+y = -6 and 5x-3 = 7 then the solutions are x = -1 and y = -4
Factors (x - 7)(x + 2) so x = 7 or -2.
2X^2 + 5X - 10 = X^2 + 4 subtract the X^2 and 4 from each side X^2 + 5X - 14 = 0 what two factors of 14 add up to 5 ? (X - 2)(X + 7) X = 2 X = - 7
4x-7=5x-2 x=-5
5x + 2 = 7 Subtract 2 from each side: 5x = 5 Divide both sides by 5: x = 1
so start with y = -x^2 + 5x + 7 then complete the square: = -(x^2 -5x -7) = -(x^2 -5x + 4/25 - 7 -4/25) = -( (x-2/5)(x-2/5) -7 -4/25) = -(x-2/5)^2 -(7 4/25)
7
7
3x + 2 + 2x = 7; 3x + 2x = 5x, so 5x + 2 = 7; 7-2=5, so 5x=5. 5x divided by 5 and 5 divided by 5 equals 1, so x equals 1.
-2