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(1/2s)+(1/5x)+7

5s+2x+7

5s=2x+7

s=2/5x+7/5

(1/2(2/5x+7/5))+(1/5x)+7

1/5x+3.5/5+1/5x+7

2/5x+7 7/10

2/5x=-7 7/10

x=-19.25

(1/2s)+(1/5x)+7

1/2s-3.85+7

1/2s+3.15

1/2s=-3.15

s=-6.3

(1/2s)+(1/5x)+7

1/2(-6.3)+1/5(-19.25)+7

-3.15-3.85+7

0

In the end, it equals 0 because there were no values for x and s and since I started with just an equation with nothing on the other side, I used (by default) 0 on the other side.

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