100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625, 676, 729, 784, 841, 900, and 961: a total of 22.
The smallest 5-digit integer perfect square is 10,000 = (100)2The largest 5-digit integer perfect square is 99,856 = (316)2So we want to know how many numbers that is, from 100 to 316 inclusive.It's 316 minus the first 99 = 217 of them.
69
878 three digit numbers have an even number of factors. Every factor of a number has a pair, so there ought to be an even number of factors for every number. However, if a pair of the factors are the same number, then there will be an odd number of factors, that is if the number is a perfect square. Assuming three digit numbers are 100 to 999: From 100 to 999, the perfect squares are 102 = 100 to 312 = 961, a total of 31-10+1 = 22 numbers. So of the 999-100+1 = 900 three digit numbers, 22 have an odd number of factors, so 900-22 = 878 have an even number of factors.
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
450
102 = 100 which is the first possible three digit number that is a perfect square. 312 = 961 which is the last possible three digit number that is a perfect square. So there are 22 three digit positive numbers that are perfect squares.
none
The smallest three-digit number is 100, and the largest is 999. The smallest integer whose square is a three-digit number is 10 (since (10^2 = 100)), and the largest integer is 31 (since (31^2 = 961)). Therefore, the three-digit perfect squares correspond to the integers from 10 to 31, which gives us a total of (31 - 10 + 1 = 22) three-digit perfect squares.
There are a total of 5 positive three-digit perfect cubes that are even. To find this, we first determine the range of three-digit perfect cubes, which is from 46 to 96. Then, we identify the even perfect cubes within this range, which are 64, 216, 512, 729, and 1000.
The smallest 5-digit integer perfect square is 10,000 = (100)2The largest 5-digit integer perfect square is 99,856 = (316)2So we want to know how many numbers that is, from 100 to 316 inclusive.It's 316 minus the first 99 = 217 of them.
To find how many two-digit numbers have digits whose sum is a perfect square, we first note that the two-digit numbers range from 10 to 99. The possible sums of the digits (tens digit (a) and units digit (b)) can range from 1 (1+0) to 18 (9+9). The perfect squares within this range are 1, 4, 9, and 16. Analyzing each case, we find the valid combinations for each perfect square, leading to a total of 36 two-digit numbers whose digits sum to a perfect square.
69
There are no four-digit perfect squares that are palindromes.
It is a natural number. It is a positive integer. It is a positive rational number. It is a positive real number. It is a perfect square. It is a three digit integer. It is a palindromic integer. Probably many other sorts.
Six: 0, 1, 4, 5, 6 and 9
To find how many numbers from 10 to 93 have the sum of their digits equal to a perfect square, we first identify the possible perfect squares within the range of digit sums. The digit sum of a two-digit number ranges from 1 (for 10) to 18 (for 93). The perfect squares in this range are 1, 4, 9, and 16. By calculating the digit sums for each number from 10 to 93, we can determine that the numbers with digit sums equal to these perfect squares are 10-19 (sum = 1, 4, 9), and some others up to 93, yielding a total of 38 numbers.
Total number of 2-digit numbers = (99 - 9) = 90 of themEvery number that isn't a perfect square has an even number of factors.2-digit numbers that are perfect squares: 16, 25, 36, 49, 64, and 81 = 6 of themRemaining 2-digit numbers = (99 - 6) = 93 .