If the order of the pairs of numbers doesn't matter (that is the pairs (1, 11) and (11, 1) are considered the same) then there are 89 such pairs.
If the order does matter (that is the pairs (1, 11) and (11, 1) are considered different) then there are 178 such pairs.
There must be one number larger than the other.
The smaller number must be at least 1, so the larger number must be at least 11.
The larger number must be at most 99, so the smaller number must be at most 89.
Thus, looking at the smaller numbers, it can be one of the numbers 1 to 89 - a total of 89 possibilities - each of which has a corresponding larger number.
Therefore there are 89 combinations of 2 integers from the number 1-99 that have a difference of 10.
If however, the order of the integers is important, then the smaller number can be the first number or second number, which means that there are twice as many possible pairs, giving 178 permutations of 2 integers from the numbers 1-99 that have a difference of 10.
There are 30 such integers.
Start with "-3", then add one at a time to get as many consecutive integers as you want.
Coding is more general -- there are many kinds of codes and different reasons for them. However, when it comes to computer slang, there is no difference between coding and programming.
There are many of them. -2,-1,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16...
the basic difference between them is that in greedy algorithm only one decision sequence is ever generated. where as in dynamic programming many decision sequences are generated.
750
A sample of 5 integers selected is shown. Does this sample represent the general rule for picking an integer from 1 to 25 in the population of integers from 1 to 1,000? Explain.
952 of them.
9000 integers.
there are 10 integers
An infinite amount
There are 30 such integers.
There are 9 integers.
None. But there are three integers there.
There are 11 integers between -4 and 8.
There are 22 integers between them.
333 integers.