12*(90%)=10.8=X*.25
10.8/.25=X=43.2
43.2-12=31.2
31.2 grams of water must be added
add 25ml more of solution x * 20 = 100 * 25 x = 25
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
This is an algebra problem. There will be 2 equations and 2 unknowns. Let x = amount of 7% solution, and y = amount of 19% solution. .07x + .19y = .15*456. x + y = 456; or x = 456-y which will substitute into the first equation. .07(456-y) +.19y = .15*456. 31.92-.07y+.19y = 68.4. .12y = 36.48. y = 304L (amount of 19% solution to add). x = 456-y. x = 456 - 304. x = 152L (amount of 7% solution to add).
60% solution contains 6/10 x 30 ie 18 litres 18 + A = 3/4 (30 + A) 72 + 4A = 90 + 3A 4A - 3A = 90 - 72 A = 18 ie add another 18 litres, giving 36 litres out of 48 which is the required 75%.
Any irrational number, when added to 13, will produce an irrational number.
If iodine solution is added to a leaf, it will turn blue-black in color. This is due to the presence of starch in the leaf which reacts with iodine to produce this color change.
Potassium iodide (KI) is added to prepare iodine solution because it helps dissolve iodine (I2) in water, increasing its solubility and stability. This results in a more concentrated solution that is easier to work with for various applications, such as in titrations or as an antiseptic.
The organic compound that reacts with iodine in a starch solution is amylose, which is a polysaccharide and a component of starch. When iodine is added to a starch solution, it forms a blue-black complex with the amylose present in the solution.
Because Iodine is a brown element.
add 25ml more of solution x * 20 = 100 * 25 x = 25
Yes, the amount of potassium iodide added in potassium (V) iodate solution will affect the amount of iodine liberated because potassium iodide reacts with potassium (V) iodate to produce iodine. Increasing the amount of potassium iodide will result in more iodine being liberated.
Sulfuric acid is added to the bleach and iodide solution to acidify the solution and promote the reaction between hypochlorite and iodide to produce iodine. The iodine produced is then titrated with sodium thiosulfate to determine the concentration of hypochlorite in the sample. Acidifying the solution helps in stabilizing the generated iodine for a more accurate titration.
A dark blue/black color develops when iodine solution is added to starch solution. This color change occurs due to the formation of a starch-iodine complex, where the iodine molecules interact with the helical structure of the starch molecules, resulting in the blue/black color.
Lead nitrate solution + sodium iodine solution -> lead iodide (solid) + sodium nitrate solution
Iodine turns blue-black when added to a protein solution such as starch. This color change indicates the presence of complex polysaccharides like glycogen or amylose.
Crisps are made from potatoes which are very high in starch. When iodine is added to starch it forms a complex with it and results in a purplish color. you get the same thing if you put an iodine sol'n on bread or cornstarch.
The color change that occurs when iodine solution is added to starch is a dark blue or purple color. This reaction is commonly used to test for the presence of starch in a solution.