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(w+5)(4w+2) - 270 = (4w)(w) 4w2 + 22w + 10 - 270 = 4w2 22w = 260 w = 11.81818181 Length = 4w = 47.2727 or 47 3/11

Width = 11.8181 or 11 9/11

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Q: How would you describe a rectangle?

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For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.

The width of the rectangle would be 32.5 meters.

Look at it this way, suppose x is one side of the rectangle and y is the other. Then the area of the rectangle would be xy. Now if you double each side of the originial rectangle you would have each side as 2x and 2y. So the area of the new rectangle would be 2x*2y or 4xy. As you can see the new area is 4 times larger than the original.

The rectangle would have a width of 2 and a length of 4.

The length and width can't be determined since it is a rectangle. A length would need to be given, or it would have to be a square.

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