square
The perimeter of rectangle A would then be 80 because 80 to 100 is 4 to 5 simplified and the area of triangle A would depend on the sides and area of rectangle B which have not been given.
The perimeter would be 40.
300
The rectangle would be shaped like any other rectangle. To find the perimeter, add all four sides together. perimeter = 50ft + 50ft + 25ft + 25ft = 150ft
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
The perimeter of rectangle A would then be 80 because 80 to 100 is 4 to 5 simplified and the area of triangle A would depend on the sides and area of rectangle B which have not been given.
The perimeter would be 40.
The perimeter would be 36 inches.
300
The width of the rectangle would be 32.5 meters.
The rectangle would be shaped like any other rectangle. To find the perimeter, add all four sides together. perimeter = 50ft + 50ft + 25ft + 25ft = 150ft
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
The perimeter would be 28 meters.
If it was a square, which is a rectangle, the perimeter would be 24 meters . But it was a regular rectangle than it could be a few things actually , one of them would be 26 meters . Another would be 40 meters I think .
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
Would be congruent.It doesn't have to be a rectangle, though.It could be any shape.