You can factor this multivariate polynomial (a polynomial with several variables, here x and y), by looking at it as a univariate polynomial in either x or y.
This would give you a simple second order equation of the form ax2+bx+c, which you can solve. This will give you 2 solutions, say x1 and x2, and can then factor your polynomial to a(x-x1)(x-x2).
In our case:
a=8, b=-y and c=-7y2
and the solutions for this equation are x1=y and x2=-7/8*y
and this gives us
8x2 - xy -7y2 = 8(x-y)(x+7/8y) = (x-y)(8x+7y)
Yx7y = 7y2 (squared )
7y
(7y^2 - 9)(7y^2 + 9)
(7y2-2y+3)-(6y2-2y+9)
(7y - 5)(y + 1)
(x - 7)(y - 2)(y + 2)
Zero. There is no term with just y in it.
That factors to y(y2 + 7y - 5)
By following the directions in your textbook. Or you could try paying attention in class; that would probably work too.
Just use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + CJust use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + CJust use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + CJust use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + C
Since 49y^8 is a multiple of 7y^2, it is automatically the LCM.
Step 1: 3(7y2 + 24y - 16) Step 2: 3(7y - 4)(y + 4) Assuming original expression was equal to zero, y = 4/7 or -4