the equation of a parabola is: y = a(x-h)^2 + k *h and k are the x and y intercepts of the vertex respectively * x and y are the coordinates of a known point the curve passes though * solve for a, then plug that a value back into the equation of the parabola with out the coordinates of the known point so the equation of the curve with the vertex at (0,3) passing through the point (9,0) would be.. 0 = a (9-0)^2 + 3 = 0 = a (81) + 3 = -3/81 = a so the equation for the curve would be y = -(3/81)x^2 + 3
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A parabola equation cannot be answered since it is not a question!
An equation for a parabola always has some type of irregular variable, usually a squared variable or higher.
The answer depends on the form in which the equation of the parabola is given. For y^2 = 4ax the directrix is x = -2a.
The equation does not represent that of a parabola.
The graph of a quadratic equation is a parabola