Without an equality sign the given quadratic expression can't be classed as an equation but knowing how to use the quadratic equation formula would be helpful when given such problems.
It is a quadratic equation that has 2 solutions
Using the quadratic equation formula: x = 1 or x = -10
The discriminant is 88 which means that the given quadratic equation has two different solutions for x
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
-7 therefore the quadratic equation has no real roots
It is a quadratic equation that has 2 solutions
There are no solutions to this quadratic equation because the discriminant is less than zero.
It has two equal solutions for x which are x = 2 and x = 2
Using the quadratic equation formula: x = 1 or x = -10
The discriminant is 88 which means that the given quadratic equation has two different solutions for x
The variable term, X^3, is a third order polynomial term and will render three solutions, though one of those may be zero.
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
-7 therefore the quadratic equation has no real roots
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
Some plusses and/or minuses would have assisted. (2x - 5)(x + 6) are factors of 2x2 + 7x - 30, giving solutions for x of 2.5 and -6; (2x + 5)(x - 6) are factors of 2x2 - 7x - 30, giving solutions of -2.5 and 6.
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2