It is a quadratic equation that has 2 solutions
Using the quadratic equation formula: x = 1 or x = -10
The discriminant is 88 which means that the given quadratic equation has two different solutions for x
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
-7 therefore the quadratic equation has no real roots
It is a quadratic equation that has 2 solutions
There are no solutions to this quadratic equation because the discriminant is less than zero.
It has two equal solutions for x which are x = 2 and x = 2
Using the quadratic equation formula: x = 1 or x = -10
The discriminant is 88 which means that the given quadratic equation has two different solutions for x
The variable term, X^3, is a third order polynomial term and will render three solutions, though one of those may be zero.
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
-7 therefore the quadratic equation has no real roots
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
Some plusses and/or minuses would have assisted. (2x - 5)(x + 6) are factors of 2x2 + 7x - 30, giving solutions for x of 2.5 and -6; (2x + 5)(x - 6) are factors of 2x2 - 7x - 30, giving solutions of -2.5 and 6.
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2