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What is 3x minus 5x plus x?
3x - 5x + x = -x
How do you solve 5x-2 3x-6?
5x-2 = 3x-6 5x = 3x - 6 +2 5x = 3x - 4 5x - 3x = -4 2x = -4 x = -2
3x plus 2 equals 5x?
3x+2 = 5x so 2x = 2 and hence x = 2/2 = 1
What is the value of x if 5x - 3 equals 4 - 3x?
The value of x is: x=7/8. Work: 5x-3=4-3x +3 +3 ________ 5x=7-3x +3x +3x ________ 8x=7 /8 /8 ________ x=7/8
What is the derivative of YX5 X3 X2 x?
y = x^5 + x^3 + x^2 + x y' = 5x^(5 - 1) + 3x^(3 - 1) + 2x^(2 -1) + 1x^(1 - 1) (note x^1 = x and x^0 = 1) y' = 5x^4 + 3x^2 + 2x + 1
3x plus 5x equals -8 then x plus 1 equals?
If 3x + 5x = -8, what is x + 1? 3x + 5x = -8 8x = -8 x = -1 x + 1 = -1 + 1 = 0
What is 3x squared plus 5x plus 2?
3x2 + 5x + 2 is a quadratic expression that can be factored as follows: 3x2 + 5x + 2 = 3x2 + 3x + 2x + 2 = 3x(x + 1) + 2(x + 1) = (3x + 2)(x + 1)
What is 3x minus 5x plus x?
3x - 5x + x = -x
What is the answer to 5x-3x plus x plus 8 equals 2x plus 1 plus x plus x?
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
Factorize completely 3x2-5x plus 2?
If you meant 3x2 - 5x + 2, here is your answer 3x2 - 5x +2 = 0 => 3x2 - 3x - 2x + 2 = 0 => 3x(x-1) - 2(x-1) = 0 => (3x - 2) (x-1) = 0 => x = 2/3 or, x = 1
What is the solution to 8x-19 equals 3x plus 1?
8x - 19 = 3x + 1 5x -19 = 1 5x = 20 x = 4
2x-4 plus 3 equals 5x-6?
x=1 2/3 How?: 2x-4+3 = 5x-6 2x-1 = 5x-6 2x-1+1 = 5x-6+1 2x = 5x-5 2x-5x = 5x-5x-5 -3x = -5 -3x/-3 = -5/-3 x = 5/3 x = 1 2/3
-5x-3x² plus 2 equals 0?
(-3x+1)(x+2) = 0 x = -2 or x = 1/3
How do you solve 5x-2 3x-6?
5x-2 = 3x-6 5x = 3x - 6 +2 5x = 3x - 4 5x - 3x = -4 2x = -4 x = -2
5x3-3x plus 4 -3x3-2x2 plus 6x-1?
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
Which expression is equivalent to 5x(x 2) -3(x-1)?
If you mean: 5x(x+2)-3(x-1) then it is 5x^2 +10x-3x+3 or as 5x^2 +7x+3
How do you solve 2xplus 1 over 3x equals xminus 1 over 5x?
one way to solve an equation in this format, "a/b = c/d", is to multiply both sides by "b"and by "d". You're effectively "cross multiplying" the fractions: (2x + 1) / 3x = (x - 1) / 5x ∴(2x + 1)(5x) = (x - 1)(3x) ∴10x2 + 5x = 3x2 - 3x You can then factor an "x" out of both sides ∴10x + 5 = 3x - 3 And rearrange to solve: ∴10x - 3x = -3 -5 ∴7x = -8 ∴x = -8/7
