-2(x + 5)(x - 6)
8
3x2+x-2 = (3x-2)(x+1) when factored
Two factors of 6 that add to -5? Try -2 & -3... (x - 2)(x - 3)
(8x^2y^2)/92(4x^2-y^2)/92(2x+y)(2x-y)/9Factored and reduced.
It is: 2(11x+3) when factorized
-2(x + 5)(x - 6)
8
I could factorize : (3 + x) (17 + 3 x) But have no idea about the next part...
3x2+x-2 = (3x-2)(x+1) when factored
Two factors of 6 that add to -5? Try -2 & -3... (x - 2)(x - 3)
4a2 - 20ab2 + 25b4 (2a - 5b2)(2a - 5b2) (2a - 5b2)2
(8x^2y^2)/92(4x^2-y^2)/92(2x+y)(2x-y)/9Factored and reduced.
27y3 + 125z3 = (3y + 5z)*(9y2 - 15yz + 25z2).
the answer is 2-5w
2(5v + 6u)
You need to look for two numbers, which multiply to 6 and add to 5. Think about the factors of 6: 1 x 6, or 2 x 3, so try 2 & 3. (a + 3)(a + 2) is the solution.