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If Leah is 6 years older than Sue and John is 5 years older than Leah and the total of their agea is 41 then how old is Sue?
The sum of the three kids ages is 41. So we can say that S+J+L=41 We know that Leah is years older than Sue. So we can write her age as L=S+6. We also know that John is 5 years older than Leah. So we can write his age as J=L+5 Since L=S+6 we can write J as S+6+5 or J=S+11 Now we have all three kids ages as terms of Sue's age. S S+6 S+11 Now we add those together and set them equal to 41. 3S+17=41 3S=24 S=8 Sue is 8 years old.
How many time is Rachel mentioned in the Bible?
which Rachel? Rachel wife of Jacob, is specifically mentioned by her name 44 times Not sure about Rachel in relation to Leah, or Rachel in relation to John
What name goes with Leah as the middle name?
sydney
Who are the biblical matriarchs?
Srah, Rebecca, Rachel and Leah.
Who was the first blind women in the Bible?
mary
Leah is 6 years older than Sue and John is 5 years older than Leah The total of their ages is 41 How old is Sue?
8
If Leah is 6 years older than her sister sue and john is 5 years older than Leah and the total of their ages is 41 how old is sue?
30 duhh!your a idiot...... its 8
If Leah is 6 years older than Sue and John is 5 years older then sue and all ages total 41 how old is sue?
Sue is 10. Leah is 16 John is 15 Making the combined ages 41.
If Leah 6 yrs older than sue and john is 5 yrs older than Leah and the total of their ages is 41 how old is sue?
Sue -- 8 Leah -- 14 John -- 19
If Leah is 6 years older than her sister Sue and John is 5 years older than Leah and the total of their ages is forty one the how old is Sue?
Sue is 8 years old. Sue (8) + Leah (14) + John (19) = 41 Solve algebraically by stating all ages in terms of Leah's (L) Sue S = L - 6 (Leah = Sue + 6) John J = L + 5 (Leah = John + 8) S + J + L = 41 (L-6) + (L+5) + L = 41 3L -1 = 41 3L = 42 L = 14 S = 8 J = 19
If Leah is 6 years older than sue and john is 5 years older that Leah and the total of their ages is 41 how old is sue?
use an equation x=sue x+x+6+x+11=41 -17 -17 3x= 24 /3 /3 x= 8 sue is 8
If Leah is 6 years older than Sue and John is 5 years older than Leah and the total of their agea is 41 then how old is Sue?
The sum of the three kids ages is 41. So we can say that S+J+L=41 We know that Leah is years older than Sue. So we can write her age as L=S+6. We also know that John is 5 years older than Leah. So we can write his age as J=L+5 Since L=S+6 we can write J as S+6+5 or J=S+11 Now we have all three kids ages as terms of Sue's age. S S+6 S+11 Now we add those together and set them equal to 41. 3S+17=41 3S=24 S=8 Sue is 8 years old.
If Leah is 6 years older than Sue and John is 5 years older Leah and the total of their ages is 41 how old is Sue?
Let L be the age of Leah, J as the age of John, and S as the age of Sue.Equation 1: S = L - 6Equation 2: J = L + 5Equation 3: L + J = 41Using Equation 3 to get Leah's age:L + J = 41L + (L + 5) = 412L = 41 - 5L = 18Using Equation 2 and substituting L to get John's age:J = L + 5J = 18 + 5J = 23Check using Equation 3, substituting L and J:L + J = 4118 + 23 = 41Using Equation 1 , substituting L to get Sue's age.S = L - 6S = 18 - 6S = 12Sue is 12 years old.Leah is 18 years old.John is 23 years old.
How many years did Jacob serve Leah and arachel?
Jacob served a total of 14 years for Leah and Rachel. He worked seven years for Leah, whom he was initially promised, and then another seven years for Rachel, whom he loved. This arrangement is detailed in the Book of Genesis in the Bible.
When was John Leah born?
John Leah was born on 1978-08-03.
How many years did Jacob work for a wife?
Jacob worked a total of 14 years for his wives, Leah and Rachel. He initially worked seven years to marry Rachel, but was deceived into marrying Leah first. After marrying Leah, he then worked another seven years to marry Rachel, the woman he loved.
Who is older Leah clearwater or her brother?
Leah is older her brother seth is like 14 and shes either 17 18 or 19 hope that helps answer ur question
