If RS = 23-2x, ST = 9x -5, and RT = 39, find RS.
65
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
3x plus 9 equals what?
The variable term, X^3, is a third order polynomial term and will render three solutions, though one of those may be zero.
2x2 + 6x - 8 = 72 ∴ 2x2 + 6x + 64 =0 ∴ x2 + 3x + 32 = 0 This can not be factored, as x is not equal to any integer. Using the quadratic equation, we find that: x = -3/2 ± √119 / 2i
2x2 equals 5
No.
2x2 + 3x - 20 = (x + 4)(2x - 5).
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
The discriminant is 1.
2x2 + 3x + 1 = (x + 1)(2x + 1)
d/dx 2x2+3x+7=4x+3
65
(2x - 1)(x - 1) so x = ½ or 1
factorises as (2x + 1)(x + 1) so x = -0.5 or -1
-11
B- It is a many-to-one function