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Jerry is experimenting with chemicals in the laboratory He mixes a solution that is 10 percent acid with a solution that is 30 percent acid How much of the 10 percent acid solution will be needed to m?
10 liters
A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
What is a possible effect of an error during transcriptions?
The wrong amino acid will be used
What does a Ka value of approximately 1 show about the equilibrium?
some of the acid has dissociated APEX
How many liters of water must be added to 7 liters of a 20 percent acid solution to obtain a 10 percent acid solution?
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
How much acid is required to give 18000 gallons of water a 30 percent acid solution?
It will not be accurate, as mixing 1 gallon of acid with one of water will not make 2 gallons. But approximately 7714 gallons of 100% acid would be needed to make a 30% volume/volume acid solution. Your problem now is that very few liquid acids come as 100%, and most that do are very dangerous around water.
How much pure acid should be mixed with 4 gallons of a 50 percent acid sollution in order to get an 80 percent acid solution?
Assuming that you mean that your pure acid is twice as concentrated as your 50% acid. Pretending your pure acid is at 1 mol/gallon and the 50% acid is 0.5 mol/gallon1 molgallon-1 * x gallons = x mol0.5 molgallon-1 * 4 gallons = 2 mol(x + 2) mol for (x+4) gallons = 0.8(x+2) mol / (x+4) gallons= 0.8 molgallon-1x + 2 = 0.8x + 3.20.2x = 1.2x = 6add 6 gallons of pure acid to the 4 gallons to make 10 gallons of 80% acid solution
How many cubic feet is 16 gallons of muratic acid?
It makes no difference what's in the 16 gallons, or whether they're empty.(16 gallons) x (231 cubic inches per gallon) / (1,728 cubic inches per cubic foot) = 2.1389 cubic feet (rounded)
How much pure acid should be mixed with 6 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
How many gallons are in one pound of phosphoric acid?
The conversion rate from pounds to gallons depends on the specific gravity of the substance. For phosphoric acid, which has a specific gravity higher than water (around 1.88), one pound would be approximately 0.22 gallons.
How do you convert Acid in tons to gallons?
The answer will depend on the acid, which do not have the same density.
How many gallons does a hydrochloric acid tanker truck have?
about 5000 gallons to 200 gallons they are all different sizes
How may gallons of hydrochloric acid would it take to neutralise 130 gallons of sodium hydroxide?
Also the concentration of HCl and NaOH are needed to be known (not only the amounts) to answer this question.
How much pure acid should be mixed with 5 gallons of a 20 percent acid solution to get a 50 percent acid solution?
x = amount of acid to add. y = final volume. 5 gal + x = y original amount of acid + acid added = final amount of acid (5 X .2) + x = O.5y Subtract the second equation from the first one. 5 - 1 + x - x = y - 0.5y 4 = 0.5y 8 = y Therefore the final volume is 8 gallons. 5 gal + x = 8 x = 3 gal. the amount of pure acid to add. Check the answer 5 X .2 = 1 gal of acid in original solution. 3 gallons added = 4 gallons total acid in solution. 4 gallons total acid in final solution of 8 gallons total solution = 50% acid.
How many gallons of a 80 percent acid solution must be mixed with 60 gallons of a 16 percent solution to obtain a solution that is 60 percent?
Let x be the gallons of the 80% acid solution needed. The amount of acid in the 80% solution is 0.8x, and the amount in the 16% solution is 0.16*60=9.6. We want a total of (x+60) gallons of solution with 60% acid, so we have the equation 0.8x + 9.6 = 0.6(x+60). Solving for x gives x = 24 gallons.
How much water should be added to 3 gallons of pure acid in order to obtain the 15 acid solution?
You need 17 gallons for a 15% volume/volume mixture.
How much water should be mixed with 2 gallons of a 50 percent acid solution in order to get an 2 percent acid solution?
To get a 2% acid solution, you need to dilute the 50% acid solution with water. Since the final volume is 2 gallons, you will need to mix 2 gallons of water with the 2 gallons of 50% acid solution to get a 2% acid solution.
