The flag pole would be 20 feet. (You can see that the shadows are twice as long.)
At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects.
Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
To calculate that, you'd need to know the angle of the light source or the time of day or have some other object to compare it to.
It is approx 36.6 ft.
To solve this problem, we can set up a proportion using the similar triangles formed by the flagpole and its shadow, and the mailbox and its shadow. The height of the flagpole to its shadow is 30 feet to 12 feet, which simplifies to 5:2. Using this ratio, we can determine the height of the mailbox by setting up the proportion 5/2 = x/1.5 (converting 18 inches to feet). Solving for x, the height of the mailbox would be 3.75 feet.
1.8 meters. The ratio of object to shadow is 10:6. Therefore if the object is 3, the shadow is 1.8 ( 6/10x3).
488 cm
Ten is to two as 40 is to x, yielding: 200ft.
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
The flagpole is 15.92 metres, approx.
21 ft how is the equation to give you this result
Using trigonometry its height is 12 feet
It works out as: 42.353 feet tall rounded to 3 decimal places
The height of the flagpolle is 26.25 feet
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
To calculate that, you'd need to know the angle of the light source or the time of day or have some other object to compare it to.
It is approx 36.6 ft.
84 feet tall
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?