250(x) = 400,000 Use logs to base '10' Hence log250^(x) = log400,000 xlog250 = log 400,000 Notirce how the power (x) becomes the coefficient. This is oerfectly correct under 'log' rules. x = log 400,000 / log 250 (NOT log(250/400,000). x = 5.60206 / 2.39794 x = 2.33619689..... ~ 2.33619 to 5 d.p.
log (6x + 5) = 26x + 5 > 06x + 5 - 5 > 0 - 56x > - 56x/6 > -5/6x > -5/6log (6x + 5) = 210^2 = 6x + 5100 = 6x + 5100 - 5 = 6x + 5 - 595 = 6x95/6 = 6x/695/6 = xCheck:
250 km in 5 hours = 250/5 = 50 km per hour.
5log563 ≈ 12.87
2logx-log5=-2 logx^2-log5=-2 log(x^2 / 5)=-2 x^2 / 5 = 10^-2 x^2=5(1/100) x^2=1/20 x=√(1/20)
250(x) = 400,000 Use logs to base '10' Hence log250^(x) = log400,000 xlog250 = log 400,000 Notirce how the power (x) becomes the coefficient. This is oerfectly correct under 'log' rules. x = log 400,000 / log 250 (NOT log(250/400,000). x = 5.60206 / 2.39794 x = 2.33619689..... ~ 2.33619 to 5 d.p.
3√250 = 15√10 The cube root of 250 is 5 times the cube root of 2.
Expressed as a percentage, 2/5 x 100 = 40 percent. % rate: = 2/5 * 100% = 0.4 * 100% = 40%
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
In index form, 250 can be expressed as 5^3. This is because 5 multiplied by itself three times (5 x 5 x 5) equals 250. Index form is a way to represent a number as a base raised to a power, where the power indicates how many times the base is multiplied by itself.
Expressed as a decimal, 29/250 is equal to 0.116.
Expressed as a decimal, 1/250 is equal to 0.004.
No, -250 cannot be a rational number because a rational number is defined as any number that can be expressed as a fraction where the numerator and denominator are both integers. Since -250 cannot be expressed as a fraction of integers, it is not a rational number.
The work done to lift the log can be calculated using the formula: Work = Force x Distance. In this case, the force is 5000 N and the distance is 5 meters. Therefore, the work required to lift the log 5 meters would be 5000 N x 5 m = 25000 Joules.
Expressed as a percentage, 75/250 x 100 = 30 percent.
7x = 5x log(7) = log(5)x = log(5) / (log(7) = 0.82709 (rounded)
Microbial load (cfu/g or cfu/ml) can be expressed as log10. So, if you have 100,000 microbes that is 5 log, 10,000 microbes is 4 log, 1,000 is 3 log, 100 microbes is 2 log and 10 microbes is 1 log. Now, if you went from 100,000 microbes cfu/g to 10,000 microbes cfu/g that would be a 1 log reduction (5 - 4 log). If you went from 100,000 to 32,000 that would be a 0.5 log reduction (5 - 4.5 log) and so on. I hope this helps St John Hall