The diagonal across a square is one of three legs in a triangle. To determine the length of a leg in a triangle a formula was developed by the ancient Greek mathematician Pythagoras. The "Pythagorean Theorum" [A sq + B sq = C sq]using the two known legs to a triangle [A and B] to determine the third. since the leg [C]. Since we are determining the diagonal across a square we already that [A=6 meters] and [B=6 meters]. So therefore the equation 6 squared [36] + 6 squared [36] = 8.484 squared [72]. So the answer to the diagonal distance across a 6 meter square is;
8.484 meters
The diagonal of the garden is 20 meters.
The diagonal is 14.142 feet.
First you need to determine the length of each side, based on knowing the diagonal (see the Related Question below). 42 / 1.4142 = 29.69876922...Once you know the length of a side, the Perimeter of the square would be 4L. So 29.69876922 x 4 = 118.795
Area of a triangle is .5 * b * h, where b is the length of the base and h is the length of the height. Here, the base from which we are measuring the height is 9 meters. So setup the problem:36 m2 = .5 * 9 m * hSolving for h yields 8 meters.
144.22yds
If the area of the square is 200, then the side is sqrt(200).The length of the diagonal is sqrt(200 + 200) = sqrt(400) = 20 meters.
The diagonal of the garden is 20 meters.
The garden's diagonal is 10 meters.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
68m
9cm
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
Each of them is 14.14 inches long. (rounded)
The area is 12.5 m2
The diagonal is 3.231 meters.
14.142 cm (rounded)
To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m