Using Pythagoras' theorem it works out as 10.5 units of measurement
To find the altitude or height of an equilateral triangle, take one-half of the length of a side of the triangle and multiple by "square root" of 3. So, if for example, the side has length 10, the height = 5 Square root of 3.
It has a perimeter of 12 units, an area of 7 (6.9282) square units and an altitude of 3.5 (3.4641) units.
Each shape has all its sides of the same length.
Answer0. All angles in an equilateral triangle have 60 degrees.
(1/2) square-root of (3) times the length of any side.
It is double the length of the base, in square units.
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
no but the diagonal divides the square into two equilateral triangles. An equilateral triangle is a triangle that has two sides of the same length
To find the altitude or height of an equilateral triangle, take one-half of the length of a side of the triangle and multiple by "square root" of 3. So, if for example, the side has length 10, the height = 5 Square root of 3.
It has a perimeter of 12 units, an area of 7 (6.9282) square units and an altitude of 3.5 (3.4641) units.
Side = 6 cm 1/2 of the base = 3 cm Altitude = 3 times square-root of 3 = 5.196 cm (rounded)
an equilateral triangle;)
If the length of a side of an equilateral triangle = 8√3, then the altitude bisects the base forming a right angled triangle. The side measuring 8√3 is the hypotenuse, the altitude (A) is one leg and half the base length is the second leg. By Pythagoras, (8√3)2 = (4√3)2 + A2 : A2 = (64 x 3) - (16 x 3) = 48 x 3 = 144 Therefore the altitude, A = √144 = 12
0.4330 times the length of a side (in square units of length)
Using Pythagoras: 62+32 = 45 and the square root of this is the altitude
It is the perimeter of a triangle times the length of the prism (in square units).
square root (3) * side length / 2