the area should double also
Answer 2
The area will quadruple. Imagine a square with sides 1 x 1. If you doubled the length of the sides you'd have a square of 2 x 2. You'd be able to get four 1 x 1 squares inside that.
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
4 x 24
To find the new area, you have to multiply the original area by the square of the scale change. For example, you have a rectangle with adjacent sides of 3 and 4. Another rectangle has the same dimensions but with triple the scale. The original rectangle's area is 12. Multiply that by 9, which is the square of the new scale, and you get an area of 108. That matches up with the area of the new rectangle, which has adjacent sides of 12 and 9.
if 3x4 is dimension of rectangle and 5 is the altitude, then, 49.035 sq. units is its surface area
Area is proportional to the square of the linear dimensions. If the linear dimensions are doubled, the area is increased by a factor of 22 = 4. The new area is 9 x 4 = 36 square inches.
If the linear dimensions of a square or a rectangle are doubled, the area of the object will be quadrupled.
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
Assuming no change in the width, yes.
It would be 4 times greater.To find this algebraically: let L be the length and W the width originallyA = L x WWhen both are doubled, the equation becomesA = (2L) x (2W) = 4LWThe area of the rectangle is quadrupled if both the length and width are doubled.
Area is quadrupled (*4) and perimeter is doubled.
If both dimensions are doubled then the area is quadrupled. This is true of any geometric shape.
The area of rectangle is : 32.0
The dimensions for area are [L2]
the area should double also Answer 2 The area will quadruple. Imagine a square with sides 1 x 1. If you doubled the length of the sides you'd have a square of 2 x 2. You'd be able to get four 1 x 1 squares inside that.
The area before would be 13.5 in2. When the length and width are doubled, the new length is 9 inches and the new width is 6 inches, giving the new rectangle an area of 54 in2. Subtract 13.5 from 54, giving you 40.5, which is the difference and the change of the area. Work A=lw A=(4.5 in)(3 in) A=13.5 in2 A=lw A=(9 in)(6 in) A=54 in2
When all of the linear dimensions are doubled . . .-- the perimeter is also doubled-- the area is multiplied by 22 = 4.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters