length = 22 meters and width = 6 meters
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14 cm
2(L+W)=P2(W+4+W)=564W+8=564W=48W=12Length is 16
Let the length be 2x-3 and the width be x:- So: 2*(2x-3+x) = 82 feet => 6x-6 = 82 => x = 14 and 2/3 Therefore the dimensions are: length = 26 ft 4 ins and width = 14 ft 8 ins
the perimeter of a rectangular rug is 40 ft. the length is 2 ft longer than the width. find the dimensions
Let the width be x, so the length is 2x - 4. Since one half of the perimeter is 26 feet ( 52/2), then we have:x + (2x - 4) = 263x - 4 = 263x - 4 + 4 = 26 + 43x = 303x/3 = 30/3x = 102x - 4 = 2(10) - 4 = 20 - 4 = 16Thus the width of the rectangular garden is 10 feet, and the length is 16 feet.