The length of the shadow at any moment is proportional to the height of the object casting the shadow. call the unknown height of the tree h, then, h/7 = 0.9/2, or
h = 7(0.9)/2 = 3 m, to the justified number of siginifcant digits, or 3.15 m if the single digit numbers given are all considered to be exact.
488 cm
The ratios are in the same proportion, so all you need to really figure out is what is in the same ratio to 20 as 6 is to 4.
The tree is 33 feet tall. Use ratios to solve this equation. 6/4 = n/22 6 x 22 = 4n 4n = 132 n = 33
h = height of tree 150 / 20 = h / 2 h = (150/20) X 2 h = ? (you figure it out)
Assuming the shadows are measured at the same time of day and that the trees are on level ground, the tree with a 20-foot shadow is a quarter longer than the tree with a 16-foot shadow. Adding a quarter of the height to 12 feet makes it 15 feet tall. Alternatively use the tangent ratio which will be opposite (height of 1st tree) over adjacent (its shadow) and multiply it by the adjacent of the 2nd tree: (12/16)*20 = 15 feet tall.
39
60
488 cm
4.5 ft
6 feet
The tree is 36.0 feet tall using the tangent ratio.
36.0 feet
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
25 feet tall
Not enough information has been given to solve this problem such as: What is the angle of elevation?
Let x= height of the tree By ratio and proportion: 6ft/4.5ft = x/15ft 4.5ft x = 6ft (15ft) x= 20ft.
The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.