A triangle with side a: 40, side b: 25, and side c: 25cm has an area of 300cm2
A cube with a face diagonal of 25cm has a surface area of 1875cm2
Area 51.
The basic formula is: A = 1/2bh where A is area, b is the base of the triangle and h is the height Using trigonometry, the area of a triangle can also be expressed as: A = 1/2absinC, where A is the area, a and b are two sides of the triangle, and C is the angle between those sides.
Area of a triangle is 1/2*Base*Height. I believe you can take it from here.
when you multiply the area of the small triangle by four it equals the area of the large triangle.
Area = 1/2 X base X height Area = 1/2 X 40cm X 25cm Area = 500 square cm
Each side is 5cm
25cm sqaured
To find the area of a regular hexagon with side length of 40cm, consider that since it is regular, then it consists of 6 equilateral triangles of side 40cm. Half of each of those triangles is a right triangle. By the pythagorean theorem, we know that if the hypotenuse is 40cm, and one side is 20cm, then the other side is the square root of (40cm squared - 20cm squared) or about 34.64cm. That makes the area of each of those 12 right triangle to be about 692.8cm, so the total area of the hexagon is about 8313.8cm.
The answer to that easy question is 25cm
(8x10) ÷ 2 = 40cm² (if units are cm)
You would first need to determine the height of the . To do this, you would make a line in the middle of the base up to the point where the two 25cm edges meet. From your knowledge of A2+B2=C2 (where A=20 B=unkown and C=25) we now know that B2=C2-A2. So, B2= 625 - 400= 225. The square root of 225 is 15. So now we know the height (B) is 15. The area of a triangle is 1/2 * Base * Height. so we have (0.5)*40*15= 300cm2. This is the area.
Its not a triangle if it has only two sides.
20cm daftie!! ^No, 25cm² actually. All you do is multiply 5 by 5.
If the sides of a triangle are doubled then the area becomes quadrupled (four times as large).
The area of triangle is : 340.0
Two sides of a triangle are not sufficient to determine its area.