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A triangle with side a: 40, side b: 25, and side c: 25cm has an area of 300cm2

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Q: What is the area of a triangle with a base of 40cm and 25cm sides?
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What is the area of a triangle that has base of 40 cm and height of 25 cm?

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How can you find the area of an isosceles triangle when the base is 40Cm and the edges 25Cm?

You would first need to determine the height of the . To do this, you would make a line in the middle of the base up to the point where the two 25cm edges meet. From your knowledge of A2+B2=C2 (where A=20 B=unkown and C=25) we now know that B2=C2-A2. So, B2= 625 - 400= 225. The square root of 225 is 15. So now we know the height (B) is 15. The area of a triangle is 1/2 * Base * Height. so we have (0.5)*40*15= 300cm2. This is the area.


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