The mean of the 6th and 7th values
first you take a group of numbers and order them from smallest to largest next you find the median or the quartile2 then you find quartile1 and 3 then you subtract quartile 1 and 3 then you have your answer :)
Well, isn't that a happy little math problem! To find the difference between the largest and smallest share, first add up the parts of the ratio: 5 + 2 + 1 = 8 parts total. Then, divide the total cash amount by 8 to find the value of each part. Finally, multiply the value of the smallest share by 5 (the ratio of the largest share) and subtract the value of the smallest share to find the difference. Happy calculating!
write these numbers in order of size smallest first 2177 914 941 944 909
the perimeter of a triangle is 86 inches. the largest side is four inches less than twice the smallest side. the third side is 10 inches longer than the smallest side. what is the length of each side?
2520
The mean of the 6th and 7th values
The mean of the 3rd and 4th values
The first quartile is the value such that a quarter of the data are smaller than that value and three quarters are larger. Since there are 8 observations, the quartile will be between the second and the third smallest values. Therefore, Q1 = (7+15)/2 = 11
yes, if all the data is the same number; when the range is zero. * * * * * That is not true. You need 25% of the values to be small, then 50% identical values, followed by 25% large values. Then the lower (first) quartile will be the same as the upper (third) quartile. The inter-quartile range (IQR) will be zero but the overall range can be as large as you like.
The lowest 25% of values.
83
41
21
The sides of the box are the quartile values: the left is the first quartile and the right is the third quartile. The width, therefore is the interquartile range.
first you take a group of numbers and order them from smallest to largest next you find the median or the quartile2 then you find quartile1 and 3 then you subtract quartile 1 and 3 then you have your answer :)
The value of any element in the third quartile will be greater than the value of any element in the first quartile. But both quartiles will have exactly the same number of elements in them: 250.
50