the perimeter of a triangle is 86 inches. the largest side is four inches less than twice the smallest side. the third side is 10 inches longer than the smallest side. what is the length of each side?
13, 12,5
Well if two triangles have sides of the same length, then by SSS they are congruent. In addition, if they have sides of the same length, their perimeters would be the same. So at first it seems like the answer would be yes. However, if is easy to come up with two triangles with the same perimeter whose sides do not have the same length Triangle 1 has sides 10, 15 and 30 to know if this is a triangle, we need the length of any side to be less the sum of the other two sides. So 10
The ratios of areas are the squares of the ratio of lengths (and the ratio of volumes are cubes of the ratio of lengths). As the perimeter of the second is twice the perimeter of the first, each length of the second is twice the length of the first, and so the ratio of the lengths is 1:2 Thus the ratio of the areas is 1²:2² = 1:4. Therefore the surface area of the larger prism is four times that of the smaller prism.
You cannot. First of all you need to assume that the figure in question is a quadrilateral and not a triangle of polygon with 5 or more sides. Even so, for a given perimeter there are infinitely many combinations of length and width. Here is an illustration, using perimeter = 12 units (L,W) = (3,3), (3.1,2.9), (3.01,2.99) In general, L = any number, rational or irrational, between 3 and 6 and W = 6-L will result in the perimeter being 12.
You can write equations for each of the two facts provided, then solve the equations. If you call the length "l", and the width "w", the facts are:3 more than...: w = 2l+3 perimeter: 2(l+w)=60 This is fairly easy to solve if you replace the first equation in the second (in the second equation, replace "w" by the expression that is on the right, in the first equation).
Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)
Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)
5,12,13
13, 12,5
Let's denote the perimeter of the first triangle as P. Since the triangles are congruent, the perimeter of the second triangle is also P. The sum of their perimeters is then 2P. According to the given statement, this sum is three times the perimeter of the first triangle. So we have the equation 2P = 3P. Simplifying, we find that P = 0, which is not a valid solution. Therefore, there is no triangle for which the sum of the perimeters of two congruent triangles is three times the perimeter of the first triangle.
No. In the first place, the word is "multiply", not "times", and in the second place, to get the width you divide the perimeter by two and then subtract the length (there are alternative methods, but none of them is even close to multiplying the length by the perimeter).
It depends on two things. First, one length, by itself, does not define a triangle. And second, it depends on what the question about the triangle is!
100 - (2 x 36) = 28 cm
The perimeter of a square is four times the length of one side. Since the length of the side is not given here, you have to figure that out first. Note that the area of a square is the square (the second power) of the length of one side.
Let the length be 6x and the width be x: 2(6x+x) = 98 12x+2x = 98 14x = 98 x = 7 Therefore: length = 42 cm and width = 7 cm Area = length*width = 294 cm2
Yes, your statement is dimensionally correct. But your formula is incorrect, and possibly ambiguous. First, the perimeter is only a simple sum involving length and width IF the figure is a rectangle. Second, the perimeter of the rectangle is double what you have stated: P = 2L + 2W
Hz