(5, 1)
3x + 2 = 82
y = 1/3x+4/3
1 and 2
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
y = 3X - 1
y = 3x + 1
1
It is: 1
y = 3x + 1 y = 3(1) + 1 y = 3 + 1 Y = 4
1
x =1, y=1
x = 1 and y = -2
y=10
y=3x+4 -3x+y=4 x=-1/3
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7