y = 1/3x+4/3
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
The equation in slope-intercept form would be y=-2x
What is the equation of the vertical line passing through (-5,-2)
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
Points: (3, 2) and (-9, 6) Slope: -1/3 Equation: 3y = -x+9
y=-x
General formula
There is no name for it except "A line perpendicular to a line segment and passing through its midpoint".
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
The equation in slope-intercept form would be y=-2x
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of the vertical line passing through (-5,-2)
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
Perpendicular lines passing through a point are at right angles to each other.
y = -(1/5)x + 9
The equation of a vertical line passing through the point (a, b) is x a.