It is a tangent.
In a right angles triangle the sides are named the hypotenuse (the side opposite the right angle) and the other two sides are called the adjacent and the opposite sides. 1) The sine of an angle = length of the opposite side ÷ length of the hypotenuse. 2) The cosine of an angle = length of the adjacent side ÷ length of the hypotenuse. Using 1) The length of the hypotenuse = length of the opposite side ÷ the sine of the angle. Using tables or a calculator obtain the sine of the angle and divide this into the length of the opposite side. The result will be the length of the hypotenuse.
Suppose ABC is a triangle. There is nothing in the question that requires the triangle to be right angled. Suppose AB is the side opposite to angle C and BC is a side adjacent to angle C. Then AB/BC = sin(C)/sin(A)
opposite/hypotenuse = sin(x) adjacent/hypotenuse = cos(x) opposite/adjacent = tan(x) where 'x' is the angle in question.
Assuming this is a right triangle. the tan of an angle is the side opposite over the side adjacent. We know the side opposite, we need to find the side adjacent, we will assign this unknown side temporarily as x. tan(15) = 1.2 / x x = 1.2 / tan(15) x (the side adjacent) is approx. 4.49 m
There are three sides, hypotenuse, opposite and adjacent. But the adjacent and opposite are not fixed sides: it depends on which of the two acute angles you are examining.For either of the non-right angles, the adjacent side is the one which forms the angle, along with the hypotenuse. For the given angle θ, the length of the adjacent side compared to the hypotenuse (adjacent/hypotenuse) is the cosine (cos θ).
Yes because tangent = opposite/adjacent
The secant of an angle in a right triangle is the hypotenuse divided by the adjacent side. The tangent angle of a right triangle is the length of the opposite side divided by the length of the adjacent side.
In a right angles triangle the sides are named the hypotenuse (the side opposite the right angle) and the other two sides are called the adjacent and the opposite sides. 1) The sine of an angle = length of the opposite side ÷ length of the hypotenuse. 2) The cosine of an angle = length of the adjacent side ÷ length of the hypotenuse. Using 1) The length of the hypotenuse = length of the opposite side ÷ the sine of the angle. Using tables or a calculator obtain the sine of the angle and divide this into the length of the opposite side. The result will be the length of the hypotenuse.
Suppose ABC is a triangle. There is nothing in the question that requires the triangle to be right angled. Suppose AB is the side opposite to angle C and BC is a side adjacent to angle C. Then AB/BC = sin(C)/sin(A)
You get the sine of the angle. For a right triangle: sin (x) = opposite/hypotenuse cos (x) = adj./hypotenuse tan (x) = opposite/adj
There is no such thing as the tangent of a triangle. Circles, angles, and conversations have tangents. In a right angled triangle, the tangent of one of the acute angles is the ratio of the length of the side opposite the angle to the length of the side adjacent to it.
By using the trigonometric ratios of Sine and Cosine. The diagonal forms the hypotenuse of a right angled triangle with the length and width of the rectangle forming the other two sides of the triangle - the adjacent and opposite sides to the angle. Then: sine = opposite/hypotenuse → opposite = hypotenuse x sine(angle) cosine = adjacent/hypotenuse → adjacent = hypotenuse x cosine(angle)
You divide the length of one adjacent side by the length of the other adjacent side.
I Am pretty sure it's a triangle(: No it's not a triangle has 3 sides i think its a trapezoid.
opposite/hypotenuse = sin(x) adjacent/hypotenuse = cos(x) opposite/adjacent = tan(x) where 'x' is the angle in question.
Third side = sqrt(hyp2 - opp2)
Suppose triangle ABC is right angled at C. Suppose you are given that the angle at B is theta. Thenif you know the length of AB (the hypotenuse), thenBC = AB*cos(theta) andAC = AB*sin(theta)if you know the length of BC, thenAB = BC/cos(theta) andAC = BC*tan(theta)if you know the length of AC, thenAB= AC/sin(theta) andBC = AC/tan(theta)