First, we have to do some mental gymnastics and decide what the question means by "different but identical".
Let's assume it's talking about two copies of the same item, like two separate identical twins.
What the question seems to be describing is the situation where both balls are rolling horizontally
across the table toward the edge. One is rolling much faster than the other, but they both reach the
edge and fall off at the same instant.
They will hit the floor at the same instant. The one that was rolling faster before the fall will hit the
floor farther from the foot of the table, but the two "clunks" as they hit will come at the same instant.
a bearing is the angle from north moving clockwise 360 degrees a negative bearing is moving counterclockwise from north
There's no proper reason. It was defined as such. Taking 1 as the denominator we can compare between two things easily like:Two trains are moving with following parametersFirst moving 500 km in 7 hrSecond moving 450 km in 6 hrWe have to determine who is faster... Now at unit (means one) hourFirst train is moving (500/7)=71.42 km per hourSecond train is moving (450/6)=75 km per hourSo clearly we can say that the 2nd train is faster.
Let us first analyse the question. The car is travelling at some speed. And it has to stop. What distance will it cover before it stops?Firstly, it is travelling at a speed of 100 kilometers per hour. And the deceleration provided is given in meters per second. So, let us convert all the data into same terms.that is, 100 kmph = 100*1000 meters per hourSo, it is travelling 100,000 metres in one hour. And one hour has 3600 secs.Hence the car is travelling 100000/3600 meters in ONE secondthat is 27.77778 or approx = 27.8 meters/second.Or simply, 100 km/hr = (100*5/18) mts/sec = 27.8 mts/secNow, we have a formula to calculate the distance covered, acceleration and deceleration provided and the initial and final speeds.v2-u2 = 2*a*s ,a is acceleration/deceleration, s is distance, v is final speed, u is initial speed.In this case, final speed is zero and deceleration = negative acceleration02-(27.8)2 = 2*(-10)*s-20*s = - (27.8*27.8)s = 38.642 metersHence the car travels a distance of 38.642 metres before it comes to a stop.
Speed X journey time. (Time actually moving).
A moving walkway is something that is used to help people move more quickly between points. They generally move at a speed of 2.5 feet per second, which makes them easy to get on and off of.
20 meters per second
the person standing on the ground, the train is moving and the ground is stationary. but the person on the train looks he is stationary and the ground is moving.
They would have to have different base velocities. One on the ground, the other in a moving vehicle.
92.2m/s
A person standing on the ground. For the person on the train, ground is moving and the train is stationary.
Jack is moving at a speed of 7.5 meters per second.
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
It means that the object is moving relative to the ground
Looking at the ground beside a moving vehicle helps you judge its
a dildo wave
show that you are moving, and in what direction