f(x) = (x + 12)2
G (x)=(x + 12)2 correct for apex.
It is f(x) = (x + 12)2or x2 + 24x + 144
Idkk
at first draw the graph of fx, then shift the graph along -ve x-axis 21 unit
Yes. For example, if you want to shift the graph 5 units to the right, you must replace every instance of "x" by "x-5".
1. Decide if the graph looks like any standard type of graph you've seen before. Is it a type of sine or cosine? A quadratic? A circle or ellipse? A line? An exponential? (You get the idea.) If you can't find a standard type to match your desired graph, pick one that looks close to it and recognize that you will be doing an approximation to your function.2. Once you have an idea of what you're graph should be like, think about the equations that are used to describe that graph. Where do the numbers go and how do they affect how the graph looks/moves/ behaves? Some functions, such as circles, hyperbolas, and quadratics, have standard equations with variables based on the important features of the graph (such as the center, maximums or minimums).3. Find the important and/or interesting parts of the graph and use them in the equation. As stated before, ellipses and such have special equations to describe them. Sines and cosines require the amplitude, frequency, and phase shift.4. Check your equation if you can. It's always good to plug a few of the points that are in your graph to make sure your equation is accurate. It's especially good to try out points you did NOT use to find your equation. If it works for these, then you probably did it right.
y = 4x + 3
To shift a funcion (or its graph) down "a" units, you subtract "a" from the function. For example, x squared gives you a certain graph; "x squared minus a" will give you the same graph, but shifted down "a" units. Similarly, you can shift a graph upwards "a" units, by adding "a" to the function.
A translation.
14
Add
If the equation is a(x-n)2+c, c causes the vertical shift. By setting the part in parenthesis, x-n, equal to 0, you can find the horizontal shift (x-n=0). I hope this helped :)
OK, so let's call the parent function you're given f(x). There's a series of transformations a parent function can go through:-f(x) = makes the parent function reflect over the x-axisOn the other hand, f(-x) = makes it reflect over the y-axisf(x+a) = makes the parent function shift a units to the leftf(x-a) = makes the parent function shift a units to the rightf(x)+a = makes the parent function shift a units upf(x)-a = makes the parent function shift a units downf(ax) if x is a fraction like 1/2 , makes the parent function stretch by a factor of 2 (or multiply each x by 2)f(ax) if x is a whole number (or fractions greater or equal to 1) like 2, makes the parent function compress by a factor of 2 (or divide each x by 2)a*f(x) if x is a fraction like 1/2, makes the parent function get shorter by a factor of 2 (or divide each y by 2)a*f(x) if x is a whole number (or fractions greater or equal to 1) like 2, makes the parent function get taller by a factor of 2 (or multiply each y by 2)One way you can always tell what to do is that everything that is INSIDE the parentheses will be the OPPOSITE of what you think it should do. OUTSIDE the parentheses will do EXACTLY what you think it should do.And when performing the transformations, start inside the parentheses first and then move outside. For example, f(x-2)+2; move the parent function first to the right 2 units and THEN move it up 2 units.
y=2/3cos(1.8b-5.2)+3.9
s shift in production function
[shift] + [F3]
FALSE
subtract
Makes the tranny shift at higher rpms when activated.
at first draw the graph of fx, then shift the graph along -ve x-axis 21 unit