To shift a funcion (or its graph) down "a" units, you subtract "a" from the function. For example, x squared gives you a certain graph; "x squared minus a" will give you the same graph, but shifted down "a" units. Similarly, you can shift a graph upwards "a" units, by adding "a" to the function.
That would be f(x) - a
it is the same as a sin function only shifted to the left pi/2 units
The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.
Yes, when you read Fx aloud can you can shorten it to F of x.
What_is_the_area_bounded_by_the_graphs_of_fx_and_gx_where_fx_equals_xcubed_and_gx_equals_2x-xsquared
y=x
Can someone please help me???
if a figure is shifted 3 units to the right, you add to the coordinate
The result depends on how the function f() is defined. Simply copy the function definition, replacing every "x" (assuming the function is defined in terms of "x") by "x+5".
y = -y implies the first line is y = 0 or the x axis. Shifted up 4 units, it becomes the line y = 4.
it is the same as a sin function only shifted to the left pi/2 units
(4,1)
The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?
It will be f(x+4).
The second graph is shifted upwards by 4 units.
The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.
-3
fx = effects = special effects