The greatest possible number of intercepts is: 2 of one axis and 1 of the other axis.
The smallest possible number of intercepts is: One of each axis.
A quadratic equation is any type of equation that can be represented as ax2 + bx + c. Example: x2 - 20x + 91 = 0. (a, b, c are known. They are the coefficients.) The coefficient of x2 is always a here. In this case, 1. The coefficient of x = b. In this case -20 (remember it's minus not plus). C is the constant. In this case that is 91. The quadratic formula is a straightforward (though it may seem complicated at first) formula which can solve any quadratic equation. http://bit.ly/1bBARRN There you have an image of the formula.
Answer It is due to the propensity of scholars of all types to label things of profound importance with words or modifications of words of a long dead language. In this case "quadratic" comes from the Latin "quadratus", meaning square. This is in fact the area of a square of a side "x" is x^2, so every equation having variable with exponent 2 become quadratic equation.
probability density function cumulative distribution function I generally use lower case for pdf and upper case for CDF, but this is far from universal.
That's not an equation - it doesn't have an equal sign. Assuming you mean 2x2 - 3x - 90 = 0, you can find the solution, or usually the two solutions, of such equations with the quadratic formula. In this case, replace a = 2, b = -3, c = -90.
Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
Yes, what you do is imagine the function "reflected" across the x=y line. Which is to say you imagine it flipped over and 'laying on its side". Functions have only one value of y for each value of x. That would not be the case for a "flipped over" quadratic function
Yes, but in this case, the coefficients of the polynomial can not all be real.
The x-intercepts of the function y = x2 + 3x + 2, can be determine by the quadratic equation which solves x2 + 3x + 2 = 0. In this case A = 1, B = 3, and C = 2. Compute x = (-B ± squareroot (B2 - 4AC)) ÷ 2A x = (-3 ± squareroot (9 - 4)) ÷ 2 x = -1.5 + squareroot (5) ÷ 2 and -1.5 - squareroot (5) ÷ 2 x ~= -0.382 and -2.618
If you have a quadratic function with real coefficients then it can have: two distinct real roots, or a real double root (two coincidental roots), or no real roots. In the last case, it has two complex roots which are conjugates of one another.
Unless the operands form an arithmetic sequence, it is not at all simple. That means the difference between successive points must be the same. If that is the case and the SECOND difference in the results is constant then you have a quadratic.
A quadratic equation is any type of equation that can be represented as ax2 + bx + c. Example: x2 - 20x + 91 = 0. (a, b, c are known. They are the coefficients.) The coefficient of x2 is always a here. In this case, 1. The coefficient of x = b. In this case -20 (remember it's minus not plus). C is the constant. In this case that is 91. The quadratic formula is a straightforward (though it may seem complicated at first) formula which can solve any quadratic equation. http://bit.ly/1bBARRN There you have an image of the formula.
2
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
Suppose you have a quadratic function of the form y = ax2 + bx + c where a, b and c are real numbers and a is non-zero. [If a = 0 it is not a quadratic!] The turning point for this function may be obtained by differentiating the equation with respect to x, or by completing the squares. However you get there, the turning point is the solution to 2ax + b = 0 or x = -b/2a Now, if a > 0 then the quadratic has a minimum at x = -b/2a and it has no maximum because y tends to +∞ as x tends to ±∞ . if a < 0 then the quadratic has a maximum at x = -b/2a and it has no minimum because y tends to -∞ as x tends to ±∞. You evaluate the value of y at this point. y = a(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c = -(b2 - 4ac)/4a In either case, if the domain of the function is bounded on both sides, then the missing extremum will be at one or the other bound - whichever is further away from (-b/2a).
write a program that reads a phrase and prints the number of lowercase latters in it using a function for counting? in C program
The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.