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Solve the system of equations 3r -4s equals 0 and 2r plus 5s equals 23?
Presumably this is a simultaneous equation in the form of: 3r-4s = 0 2r+5s = 23 Multiply all the terms in the top equation by 2 and in the bottom equation by 3: 6r-8s = 0 6r+15s = 69 Subtract the bottom equation from the top equation: -23s = -69 Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number: s = 3 Substitute the value of s into the original equations to find the value of r: Therefore: r = 4 and s = 3
If a circle with a diagonal line through it is a symbol for no solution how you designate the case when any value satisfies the equation?
When any value satisfies the equation, you would simply state "all real numbers." There is a symbol for it, and even though it is difficult to explain, I will attempt to. It is simply an R with an extra line making it kind of look like |R, but it's connected to the furthermost left parallel line. I hope that helps!
How do you solve for the Radius r in the cylinder equation V equals rh?
If v = r * h then> r = v / h
What is the radius if area equals 289 pi?
Recall the equation A = pi * r^2. You've given the information that A = 289 pi. Now, simply solve the equation for r: A = pi * r^2 289 pi = pi * r^2 289 = r^2 sqrt(289) = r 17 = r
Rx-st r which expression represents x?
x = (r + st)/r is the expression that represents x in the equation rx - st = r.
