0
y = a(x-p)(x-q)
The x intercepts of this function are (p,0) and (q,0)
This form can be derived by factoring the standard form y = ax2 + bx + c or the vertex form y = a(x-h)2 + k
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
How do you get a parabola with only one x intercept?
When the vertex lies on the x-axis. For example x = y2, the vertex is at the origin, and the parabola is lying on its side.
Write y2x 4 in slope intercept form?
y=2x+4 is in slope intercept form
What is the slope intercept form of y equals 2x?
Slope-Intercept Form: y = -2x +1
Find the equation of the line in slope intercept form slope 2 y-intercept -8?
The slope intercept form is y=mx+b where m is the slope and b is the y intercept y=2x-8.
What is the slope intercept form of the equation of a line with slope 1 over 3 and y intercept 0 -4?
y = 1/3x-4 in slope intercept form
Does a parabola have to have an x-intercept?
No, a parabola does not have to have an x-intercept. ex. -2(x-2)^2 - 4 is a parabola that has no x-intercept.
How do you find the y intercept when given a parabola in standard form?
At any point on the y-axis, the x-coordinate is zero. In the equation of the parabola, set x=0. Tidy it up, and you have " Y = the y-intercept ".
Is the y intercept a vertical line through the vertex of a parabola?
No.
What is the general shape of a graph of a quadratic function in the form yax2 c?
y = ax2 + c is a parabola, c is the y intercept of the parabola. It also happens to be the max/min of the function depending if a is positive or negative.
What is the vertex of a parabola?
the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)
How do you get a parabola with only one x intercept?
When the vertex lies on the x-axis. For example x = y2, the vertex is at the origin, and the parabola is lying on its side.
How do you find the y intercept on a parabola?
If you know the equation, you just plug in x = 0 and solve.
When would not having a parabola x- intercept happen?
Consider a parabola described by the expression y = ax2 + bx + c first, calculate it's first and second derivatives: y' = 2ax + b y'' = 2a Find x value at which y' = 0, and calculate whether the corresponding y-coordinate is above or below the x-axis. If it's above the x-axis, then the parabola will not intercept the x-axis if y'' is greater than 0. If it's below the x-axis, then the parabola will not intercept the x-axis if y'' is less than 0. Otherwise, it will always intercept the x axis at two locations.
Find the x intercept or interceptss and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
-2, 6
Find the x intercept or intercepts and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.
How do you get Plato web answer key?
find the x-intercepts of the parabola with vertex (7,-12) and y-intercept (0,135). write your answer in this form:(x1,y1),(x2,y2). if necessary, round to the nearest hundredth.
Y intercept of parabola- y equals x minus1 x plus 3?
Well, when a parabola is in the form y=ax^2+bx+c, we know that c is the y-intercept.So all we need to do with this equation is expand it into that form.y = (x-1)(x+3)Expandy = x^2-1x+3x-3Collect like termsy = x^2+2x-3And there you have it. Your y-intercept is -3.
