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Oh honey, the intercept form for a parabola is just a fancy way of saying the equation looks like y = a(x - h)(x - k). The (h, k) represents the coordinates of the vertex, and the 'a' is the same 'a' you see in vertex form - it just tells you if the parabola opens up or down. So there you have it, intercept form in a nutshell. Hope that clears things up for ya!
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How do you get a parabola with only one x intercept?
To have a parabola with only one x-intercept, the vertex of the parabola must lie on the x-axis. This means the parabola opens either upwards or downwards, depending on the coefficient of the squared term in the equation. If the coefficient is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. By adjusting the coefficients in the equation of the parabola, you can position the vertex such that there is only one x-intercept.
Write y2x 4 in slope intercept form?
y=2x+4 is in slope intercept form
What is the slope intercept form of y equals 2x?
Slope-Intercept Form: y = -2x +1
Find the equation of the line in slope intercept form slope 2 y-intercept -8?
The slope intercept form is y=mx+b where m is the slope and b is the y intercept y=2x-8.
What is the slope intercept form of the equation of a line with slope 1 over 3 and y intercept 0 -4?
y = 1/3x-4 in slope intercept form
Does a parabola have to have an x-intercept?
No, a parabola does not have to have an x-intercept. ex. -2(x-2)^2 - 4 is a parabola that has no x-intercept.
How do you find the y intercept when given a parabola in standard form?
At any point on the y-axis, the x-coordinate is zero. In the equation of the parabola, set x=0. Tidy it up, and you have " Y = the y-intercept ".
How do you get a parabola with only one x intercept?
To have a parabola with only one x-intercept, the vertex of the parabola must lie on the x-axis. This means the parabola opens either upwards or downwards, depending on the coefficient of the squared term in the equation. If the coefficient is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. By adjusting the coefficients in the equation of the parabola, you can position the vertex such that there is only one x-intercept.
Is the y intercept a vertical line through the vertex of a parabola?
No.
What is the general shape of a graph of a quadratic function in the form yax2 c?
y = ax2 + c is a parabola, c is the y intercept of the parabola. It also happens to be the max/min of the function depending if a is positive or negative.
What is the vertex of a parabola?
the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)
How do you find the y intercept on a parabola?
If you know the equation, you just plug in x = 0 and solve.
When would not having a parabola x- intercept happen?
Consider a parabola described by the expression y = ax2 + bx + c first, calculate it's first and second derivatives: y' = 2ax + b y'' = 2a Find x value at which y' = 0, and calculate whether the corresponding y-coordinate is above or below the x-axis. If it's above the x-axis, then the parabola will not intercept the x-axis if y'' is greater than 0. If it's below the x-axis, then the parabola will not intercept the x-axis if y'' is less than 0. Otherwise, it will always intercept the x axis at two locations.
Find the x intercept or interceptss and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
-2, 6
Find the x intercept or intercepts and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.
How do you get Plato web answer key?
find the x-intercepts of the parabola with vertex (7,-12) and y-intercept (0,135). write your answer in this form:(x1,y1),(x2,y2). if necessary, round to the nearest hundredth.
Y intercept of parabola- y equals x minus1 x plus 3?
Well, when a parabola is in the form y=ax^2+bx+c, we know that c is the y-intercept.So all we need to do with this equation is expand it into that form.y = (x-1)(x+3)Expandy = x^2-1x+3x-3Collect like termsy = x^2+2x-3And there you have it. Your y-intercept is -3.
